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In an circuit, V and I are given by V=15...

In an circuit, V and I are given by `V=150sin(150t) V` and `I =150sin(150t+(pi)/(3))A`. The power dissipated in the circuit is

A

zero

B

5625 W

C

150 W

D

106 W

Text Solution

Verified by Experts

The correct Answer is:
B
Power, `P=(1)/(2)V_(0)I_(0)cosphi`
`=0.5xx150xx150xxcos60^(@)`
`=(22500)/(4)=5625W`
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