In a series resonant LCR circuit the voltage across R is 100 volts and R = `1 k(Omega) with C =2(mu)F`. The resonant frequency `(omega)` is `200 rad//s`. At resonance the voltage across L is

Options

A. 100 V
B. 40 V
C. 250 V
D. 400 V

Answer

C

Explanation

The current in the circuit, `i=(V_(R))/(R)=(100)/(1000)=0.1A`
At resonance, `V_(L)=V_(C)=iX_(C)=(i)/(omegaC)`
`=(0.1)/(200xx2xx10^(-6))`
=250 V