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What will be the self inductance of a co...

What will be the self inductance of a coid of 100 turns if a current of 5 A produces a magnetic flux `5xx10^(-5)` Wb?

A

`1 mH`

B

`10 mH`

C

`1muH`

D

`10 muH`

Text Solution

Verified by Experts

The correct Answer is:
A
Self-inductance `L=(Nphi)/(I)`
`L=(100xx5xx10^(-5))/(5)=10^(-3)H=10H`
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