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When a current of 2 A is passed through ...

When a current of 2 A is passed through a coil of 100 turns , flux associated with it is `5 xx 10^(-5) `Wb. Find the self inductance of the coil.

A

`4xx10^(-3)H`

B

`4xx10^(-2)H`

C

`2.5xx10^(-3)H`

D

`10^(-3)H`

Text Solution

Verified by Experts

The correct Answer is:
C
Self-inductance, `L=(Nphi)/(i)=(100xx5xx10^(-5))/(2)`
`=250xx10^(-5)=2.5xx10^(-3)H`
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