When a rod of length l is rotated with angular velocity of `omega` in a perpendicular field of induction B , about one end , the emf across its ends is

Options

A. `Bl^(2)omega`
B. `(Bl^(2)omega)/(2)`
C. `Bl omega`
D. `(Bk omega)/(2)`

Answer

B

Explanation

A conducting rod of length l whose one end is fixed, is rotated about the axis passing through its fixed end and perpendicular to its length with constant angular velocity `omega`. Magnetic field (B) is perpendicular to the plane of the paper.
The emf induced across the ends of the rod is e=BAn

`=Bpil^(2)n=(Bl^(2)pi)/(T)=(1)/(2)Bl^(2)omega`