If a current of 10 A flows in one second...

If a current of `10 A` flows in one second through a coil and the induced e.m.f. is `10V`, then the self-inductance of the coil is

A

1 H

B

2 H

C

4 H

D

`(2)/(5)` H

Text Solution

Verified by Experts

The correct Answer is:

A

The induced emf is given by
`E=L(dI)/(dt)=Lxx(10)/(1)`
or `10=10L`
Hence, `L=1H`

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