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The current in a coil of inductance 5H d...

The current in a coil of inductance `5H` decreases at the rate of `2A//s`. The induced e.m.f. is

A

2 V

B

5 V

C

10 V

D

-10 V

Text Solution

Verified by Experts

The correct Answer is:
D
Induced emf, `e=-L(dI)/(dt)`
Here, `L=5H,(dI)/(dt)=2A//s=-5xx(2)/(1)=-10V`
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