In the Bohr model of a hydrogen atom, the centripetal force is furnished by the coulomb attraction between the proton and the electron. If `a_(0)` is the radius of the ground state orbit, m is the mass and e is the chargeon the electron and `varepsilon_(0)` is the vacuum permittivity,the speed of the electron is

Options

A. `(e)/(sqrt(epsi_(0)a_(0)m))`
B. zero
C. `(e)/(sqrt(4piepsi_(0)a_(0)m))`
D. `(sqrt(4epsi_(0)a_(0)m))/(e)`

Answer

C

Explanation

As we know, `(mv^(2))/(a_(0))=(Ze^(2))/(4piepsi_(0)a_(0)^(2))`
`implies v=(e)/(sqrt(4piepsi_(0)ma_(0)))" "[becauseZ=1]`