The ionization enegry of the electron in the hydrogen atom in its ground state is `13.6 ev`. The atoms are excited to higher energy levels to emit radiations of `6` wavelengths. Maximum wavelength of emitted radiation corresponds to the transition between

Options

A. n=3 to n=2 states
B. n=3 to n=1 states
C. n=2 to n=1 states
D. n=4 to n=3 states

Answer

D

Explanation

As, we know, `(n(n-1))/(n)=6` minimum
So, `n=4,4to3`