What will be the angular momentum in fourth orbit, if L is the angular momentum of the electron in the second orbit of hydrogen atom?

Options

A. `2L`
B. `(3)/(2)L`
C. `(2)/(3)L`
D. `(L)/(2)`

Answer

A

Explanation

We know that the angular momentum of the electron of hydrogen atom
`L_(n)=(nh)/(2pi)` . . . (i)
But according to question the angular momentum in
second orbit is L.
So, `L=(2h)/(2pi)=(h)/(pi)` . .. (ii)
Hence, the angular momentum in fourth orbit is `L_(4)'=(4h)/(2pi)`
`=(2h)/(pi)=2L`