If the binding energy of the electron in a hydrogen atom is `13.6 eV`, the energy required to remove the electron from the first excited state of `Li^(++)` is

Options

A. 30.6 eV
B. 13.6 eV
C. 3.4 eV
D. 12.24 eV

Answer

A

Explanation

Ionisatisation energy, `E=-Z^(2)(13.6)/(n^(2))eV`
For first excited state, `E_(2)=-3^(2)xx(13.6)/(4)=-30.6eV`
Ionisation energy for first excited state of `Li^(2+)` is 30.6 eV.