Taking the Bohr radius `a_(0) = 53` pm, the radius of `Li^(++)` ion in its gnround state, on the basis of Bohr's model, will be about.

Options

A. 53 pm
B. 27 pm
C. 18 pm
D. 13 pm

Answer

C

Explanation

On the basis of Bohr's model,
`r=(n^(2)h^(2))/(4pi^(2)mKZe^(2))=a_(0)(n^(2))/(Z)`
Let `Li^(2+)` ion, `Z=3,n=1` for ground state
given `a_(0)=53pm`
`therefore r=(53xx1^(2))/(3)=18`pm