In the nuclear reaction .(7)^(14)N+X to ...

In the nuclear reaction `._(7)^(14)N+X to ._(6)^(14)C+._(1)^(2)H`, the X will be

`""_(-1)^(0)e`

`""_(1)^(1)H`

`""_(1)^(2)H`

`2_(0)^(1)n`

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The correct Answer is:

Half-life of a radioactive element,
`T=(0.693)/(lamda)`
or `Tprop(1)/(lamda)`
`therefore (lamda_(A))/(lamda_(B))=(T_(B))/(T_(A))`

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