If 200 MeV energy is released in the fission of a single nucleus of `._(92)U^(235)`, how many fissions must occur per sec to produce a power of 1 kW?

Options

A. `3.12xx10^(13)`
B. `3.12xx10^(3)`
C. `3.1xx10^(17)`
D. `3.12xx10^(19)`

Answer

A

Explanation

We know that, `E=Deltamc^(2)=0.5xx10^(-3)xx(3xx10^(8))^(2)`
`=4.5xx10^(13)`
`'E=(4.5xx10^(13))/(3.6xx10^(8))=1.25xx10^(7)`