An electron is accelerated under a potential difference of 182 V. the maximum velocity of electron will be (Given, charge of an electron is `1.6xx10^(-19)C` `ms^(-1)` and its mass is `9.1xx10^(-31)kg`)

Options

A. `5.65xx10^(6)ms^(-1)`
B. `4xx10^(6)ms^(-1)`
C. `8xx10^(6)ms^(-1)`
D. `16xx10^(6)ms^(-1)`

Answer

C

Explanation

Given, `E=120eV`
We know that de-Broglie wavelength of an electron,
`lamda=(1.227)/(sqrt(E)) nm implies lamda=(1.227)/(sqrt(120))xx10^(-9)m`
`lamda=0.1120xx10^(-9)`
`implies lamda=112.0xx10^(-12)`
`lamda=112` pm