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Find the de-Broglie wavelength of an ele...

Find the de-Broglie wavelength of an electron with kinetic energy of 120 eV.

A

112 pm

B

95 pm

C

124 pm

D

102 pm

Text Solution

Verified by Experts

The correct Answer is:
A
Kinetic energy of photoelectrons `(1)/(2)mv^(2)=eV`
`(1)/(2)xx9xx10^(-31)xxv^(2)=1.6xx10^(-19)xx182`
`v^(2)=(1.6xx10^(-19)xx182xx2)/(9.1xx10^(-31))`
`v^(2)=64xx10^(2)ms^(-1) implies v=8xx10^(6)ms^(-1)`
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