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A hydrogen like ion having wavelength di...

A hydrogen like ion having wavelength difference between first Balmer and Lyman series equal 593 Å has Z equal to

A

2

B

3

C

4

D

1

Text Solution

Verified by Experts

The correct Answer is:
B

As, `(1)/(lamda)=RZ^(2)[(1)/(n_(1)^(2))-(1)/(n_(2)^(2))]`
`implies Delta lamda=(1)/(RZ^(2)((1)/(4)-(1)/(9)))-(1)/(RZ^(2)((1)/(1)-(1)/(4)))`
`implies 593=(36)/(5RZ^(2))-(4)/(3RZ^(2))`
`implies Z^(2)=(88)/(15Delta lamda)`
`=(88)/(15(1.097xx10^(7))(593xx10^(-10)))=9`
`implies Z=3`
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MHTCET PREVIOUS YEAR PAPERS AND PRACTICE PAPERS-ATOMS, MOLECULES AND NUCLEI -Exercise 2 (MISCELLANEOUS PROBLEMS)
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  16. The binding energy of the innermost electron in tungsten is 40 keV. To...

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