If, an electron in hydrogen atom jumps from an orbit of lelvel n=3 to an orbit of level n=2, emitted radiation has a freqwuency (R= Rydbertg's contant ,c = velocity of light)

Options

A. `(3Rc)/(27)`
B. `(Rc)/(25)`
C. `(8Rc)/(9)`
D. `(5Rc)/(36)`

Answer

D

Explanation

When an electron jumps from orbit `n_(i)` to orbit `n_(f)(n_(i)gtn_(f))`, the frequency of emitted photon is given by
`v=cR[(1)/(n_(f)^(2))-(1)/(n_(i)^(2))]=cR[(1)/(2^(2))-(1)/(3^(2))]=cR[(5)/(36)]=(5cR)/(36)`