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The half-life of a radioactive isotope X...

The half-life of a radioactive isotope `X` is `20 yr`. It decays to another element `Y` which is stable. The two elements `X` and `Y` were found to be in the ratio `1:7` in a sample of given rock. The age of the rock is estimated to be

A

40 yr

B

60 yr

C

80 yr

D

100 yr

Text Solution

Verified by Experts

The correct Answer is:
B

As `(N)/(N_(0))=((1)/(2))^(n)=(N)/(N_(0))=((1)/(2))^(3)=(1)/(8)`
Number of half-lives=3
`implies T=20` yr
`therefore T=(t)/(n)`
or `t=Txxn=20xx3yr=60yr`
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