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Orbital acceleration of electron is...

Orbital acceleration of electron is

A

`(n^(2)h^(2))/(4pi^(2)m^(2)r^(2))`

B

`(n^(2)h^(2))/(2n^(2)r^(3))`

C

`(4n^(2)h^(2))/(pi^(2)m^(2)r^(3))`

D

`(4n^(2)h^(2))/(4pi^(2)m^(2)r^(3))`

Text Solution

Verified by Experts

The correct Answer is:
A

`mvr=(nh)/(2pi) implies v=(nh)/(2pimr) or (v^(2))/(r)=(n^(2)h^(2))/(4pi^(2)m^(2)r^(2))`
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MHTCET PREVIOUS YEAR PAPERS AND PRACTICE PAPERS-ATOMS, MOLECULES AND NUCLEI -MHT CET Corner
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