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The de-Broglie wavelength of an electron...

The de-Broglie wavelength of an electron in the ground state of the hydrogen atom is

A

`pir^(2)`

B

`2pir`

C

`pir`

D

`sqrt(2pir)`

Text Solution

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The correct Answer is:
B
According to Bohr's theory, `mvr=(nh)/(2pi)`
`2pir=(nh)/(mv)`
`2pir=nlamda`
For `n=1,lamda=2pir`
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