The orbital frequency of an electron in the hydrogen atom is proportional to

Options

A. `n^(3)`
B. `n^(-3)`
C. `n^(1)`
D. `n^(0)`

Answer

B

Explanation

Time period of electron, `T=(4epsi_(0)^(2)n^(3)h^(3))/(mZ^(2)e^(4))`
`therefore T prop n^(3)`
`therefore (1)/("frequency (f)")propn^(3)`
or `f prop n^(-3)`