A glass slab has a critical angle of `30^(@)` when placed in air. What will be the criticle angle when it is placed in liquid of refractive index 6/5 index?

Options

A. `45^(ul(@))`
B. `37^(ul(@))`
C. `53^(ul(@))`
D. `60^(ul(@))`

Explanation

Refractive index of glass, `mu_(g)=(1)/(sin30^(@))=2`
Now, `sintheta_(C)=(6//5)/(2)=(3)/(5)`
`therefore theta_(C)=37^(@)`