When light rays are incident on a prism at an angle of `45^(@)`, the minimum deviation is obtained. If refractive index of the material of prism is `sqrt(2)`, then the angle of prism will be

Options

A. `30^(@)`
B. `75^(@)`
C. `90^(@)`
D. `60^(@)`

Explanation

Refractive index off prism,
`mu=(sin.(A+delta_(m))/(2))/(sin.(A)/(2))impliesi=45^(@)=(A+delta_(m))/(2)`
So, `(sin45^(@))/(sin(A//2))=sqrt(2)`
So, `(1)/(2)=sin.(A)/(2)impliesA=60^(@)`