Angle of minimum deviation for a prism of refractive index 1.5 is equal to the angle of prism The angle of prism is `(cos 41^(@) = 0.75)`

Options

A. `21^(@)`
B. `42^(@)`
C. `60^(@)`
D. `82^(@)`

Explanation

Refractive index of prism, `mu=(sin.((A+delta_(m))/(2)))/(sin((A)/(2)))`
Substituting `A=delta_(m)andmu=1.5`,
`1.5=(sinA)/(sin((A)/(2)))`
`(1.5)/(2)=cos.(A)/(2)`
`7.5=cos.(A)/(2)`
We get, `A=82^(@)`.