A mark at the bottom of a liquid appears to rise by `0.1m`. The depth of the liquid is `1m`. The refractive index of the liquid is

Options

A. 1.33
B. `9//10`
C. `(10)/(9)`
D. `1.5`

Explanation

Real depth = 1m
Apparent depth = 1 - 0.1 = 0.9 m
Refractive index, `mu=("Real depth")/("Apparent depth")`
`=(1)/(0.9)=(10)/(9)`