When sunlight is scattered by atmospheric atoms and molecules, the amount of scattering of light of wavelength 440 nm is A. The amount of scattering for the light of wavelength 660 nm is approximately

Options

A. `(4)/(9)A`
B. `2.25A`
C. `1.5A`
D. `(A)/(6)`

Explanation

By Rayleigh's law of scattering,
`lprop(1)/(lambda^(4))or(l_(2))/(l_(1))=((lambda_(1))/(lambda_(2)))^(4)`
`(l_(2))/(A)=((440)/(660))^(4)orl_(2)~=(A)/(2)`