" 1) "4^(sin2x+2cos^(2)x)+4^(1-sin2x+2sin^(2)x)=65

Solve the equation 4^(sin2x+2cos^(2)x)+4^(1-sin2x+2sin^(2)x)=65

If 4^(sin2x+2cos^(2)x)+4^(1-sin2x+2sin^(2)x)=65 ,then(sin2x+cos2x) has the value of equal to: -1 b dot2 c. sqrt(2) d. cospi

Solve the equation 4^(sin 2x+2 cos^2 x)+4^(1-sin 2 x+2 sin^2 x)=65

Solve the equation, 4^(sin2x + 2cos^(2)x+ 2sin^(2)x)=64 .

Solve the equation, 4^(sin2x + 2cos^(2)x+ 2sin^(2)x)=64 .

Solev (sin^(2) 2x+4 sin^(4) x-4 sin^(2) x cos^(2) x)/(4-sin^(2) 2x-4 sin^(2) x)=1/9 .

Solve (sin^(2) 2x+4 sin^(4) x-4 sin^(2) x cos^(2) x)/(4-sin^(2) 2x-4 sin^(2) x)=1/9 .

sin^(4)x+cos^(4)x=1-2sin^(2)x cos^(2)x

If f(x) = |(1+sin^(2)x,cos^(2)x,4 sin 2x),(sin^(2)x,1+cos^(2)x,4 sin 2x),(sin^(2)x,cos^(2)x,1+4 sin 2x)| What is the maximum value of f(x)?

The integral int((sin2x+cos^(2)x)dx)/(1+sin^(2)x(sin2x-cos^(2)x)) is equal to