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sin^(-1) (5/x) +sin^(-1) (12/x) =pi/2...

`sin^(-1) (5/x) +sin^(-1) (12/x) =pi/2`

Text Solution

Verified by Experts

`sin^(-1)(5/x)=pi/2-sin^(-1)(12/x)`
`pi/2-cos^(-1)(5/x)=pi/2-sin^(-1)(12/x)`
`cos^(-1)(5/x)=sin^(-1)(12/x)=theta`
`costheta=5/x,sintheta=12/x`
`sin^2theta+cos^2theta=1`
`144/x^2+25/x^2=1`
`169/x^2=1`
`x=pm13`
...
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