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In triangle ABC,a(b^2+c^2)cos A+b(c^2+a...

In triangle `ABC,a(b^2+c^2)cos A+b(c^2+a^2)cosB+c(a^2+b^2)cosC=`

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In Delta ABC prove that a(b^2 + c^2) cosA + b(c^2 +a^2)cosB + c(a^2 + b^2) cosC = 3abc

In triangleABC, a(b^(2)+c^(2))cosA+b(c^(2)+a^(2))cosB+c(a^(2)+b^(2))cosC=

Knowledge Check

  • In triangle ABC , a (b^2 +c^2 ) cos A + b (c^2 +a^2 ) cos B + c(a^2 +b^2 ) cos C is equal to

    A
    `abc`
    B
    2 abc
    C
    3 abc
    D
    4abc
  • In triangleABC, a(b^(2)+c^(2))cosA+b(c^(2)+a^(2))cosB+c(a^(2)+b^(2))cosC=

    A
    `0`
    B
    `3abc`
    C
    `3a^(2)bc`
    D
    `3ab^(2)c`
  • In triangle ABC//a(b^(2)+c^(2))cosA+b(c^(2)+a^(2))(cosB+c(a^(2)+b^(2))cosC=

    A
    `2abc^(2)`
    B
    `2a^(2)bc`
    C
    `3abc`
    D
    `2ab^(2)c`
  • Similar Questions

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    Show that in a triangle ABC, (b^2-c^2)/(cosB+cosC)+(c^2-a^2)/(cosC+cosA)+(a^2-b^2)/(cosA+cosB)=0

    If any triangle A B C , that: (b^2-c^2)/(cosB+cosC)+(c^2-a^2)/(cosC+cosA)+(a^2-b^2)/(cosA+cosB)=0

    for any triangleABC show that (b^2-c^2)/(cosB+cosC)+(c^2-a^2)/(cosC+cosA)+(a^2-b^2)/(cosA+cosB)=0

    In a triangle ABC , acosB + b cosC + c cosA =(a+b+c)/2 then

    In Delta ABC , a( b^(2) + c^(2) ) cos A +b ( c^(2) +a^(2)) cos B + c( a^(2) +b^(2)) cos C =