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A point P lies on a line whose ends are ...

A point P lies on a line whose ends are A (1,2,3) and B(2,10,1). If z-coordinate of P is 7, then point P is

Text Solution

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`(x-x_1)/(x_2-x_1)=(y-y_1)/(y_2-y_1)=(z-z_!)/(z_2-z_1)=k`
`(x-1)/1=(y-2)/8=(z-3)/(-2)=k`
`(x-1)=(y-2)/8=-2=k`
`x=1+(-2)=-1`
`y=-16+2=-14`
option 1 is corrrect.
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