(z+4z^(2)quad 13.2x^(2)-(5)/(6)x+(1)/(12)

(1)4z+3=6+2z(2)(2x)/(3)+1=(7x)/(15)+3

Verity the property: xx(y+z)=xxy+xxz by tak in g:x=(-8)/(3),y=(5)/(6),z=(-13)/(12)x=(-3)/(4),y=(-5)/(2),z=(7)/(6)

The equation of the sphere whose centre is (6, -1, 2) and which touches the plane 2x-y+2z-2=0 , is :a) x^(2)+y^(2)+z^(2)-12x+12y-4z-16=0 b) x^(2)+y^(2)+z^(2)-12x+2y-4z=0 c) x^(2)+y^(2)+z^(2)-12x+2y-4z+16=0 d) x^(2)+y^(2)+z^(2)-12x+2y-4z+6=0

The straight lines (x-3)/(2)=(y+5)/(4)=(z-1)/(-13)and(x+1)/(3)=(y-4)/(5)=(z+2)/(2) are

The equation of the line intersection of the planes 4x+4y-5z=12 and 8x+12y-13z=32 can be written as: (A) x/2=(y-1)/3=(z-2)/4 (B) x/2=y/3=(z-2)/4 (C) (x-1)/2=(y-2)/3=z/4 (D) (x-1)/2=(y-2)/(-3)=z/4

The equation of the line intersection of the planes 4x+4y-5z=12 and 8x+12y-13z=32 can be written as: (A) x/2=(y-1)/3=(z-2)/4 (B) x/2=y/3=(z-2)/4 (C) (x-1)/2=(y-2)/3=z/4 (D) (x-1)/2=(y-2)/(-3)=z/4

If z_1=5+12 ia n d|z_2|=4,t h e n (a)maximum (|z_1+i z_2|)=17 (b)minimum (|z_1+(1+i)z_2|)=13+4sqrt(2) (c)minimum |(z_1)/(z_2+4/(z_2))|=(13)/4 (d)maximum |(z_1)/(z_2+4/(z_2))|=(13)/3