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[x=(sin^(3)t)/(sqrt(cos2t)),y=(cos^(3)t)...

[x=(sin^(3)t)/(sqrt(cos2t)),y=(cos^(3)t)/(sqrt(cos2t))],[" Then find "(dy)/(dx)]

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If x=(sin^(3)t)/(sqrt(cos2t)) and y=(cos^(3)t)/(sqrt(cos2t)) , then find (dy)/(dx) .

x = (sin^3t)/(sqrt(cos 2t)), y = (cos^3 t)/(sqrt(cos 2t)) .

If x=(sin^(3)t)/(sqrt(cos2t)),y=(cos^(3)t)/(sqrt(cos2t)) show that (dy)/(dx)=0att=(pi)/(6)

If x=(sin^(3)t)/(sqrt(cos 2t)) and y=(cos^(3)t)/( sqrt(cos 2t)) , show that (dy)/(dx)=0 at t=(pi)/(6) .

x= sin^3t/sqrt x cos2t , y= cos^3t/ sqrt x cos2t .

Find dy/dx if x = (sin^3t)/(sqrtcos2t), y = (cos^3t)/(sqrtcos2t)

Find (dy)/(dx) , if x=(sin^3t)/(sqrt(cos2t)) , y=(cos^3t)/(sqrt(cos2t))