25.|[x+1,2,3],[1,x+1,3],[3,-6,x+1]|=

Solve for x: /_\=|[2x,3,1],[4,6,x],[3x,1,1]| = 0

|{:(x+1," "2," "3),(" "1,x+1," "3),(" "3,-6,x+1):}|=0

Without expanding, find the value of: (i) (x + 1)^4 - 4(x + 1)^3 (x - 1) + 6(x + 1)^2 (x - 1)^2 - 4(x + 1) (x - 1)^3 + (x -1)^4 (ii) (2x - 1)^4 + 4(2x - 1)^3 (3 - 2x) + 6(2x - 1)^2 (3 - 2x)^2 + 4(2x - 1) (3 - 2x)^3 + (3 - 2x)^4

Simplify: {(2/3)^2}^3x\ (1/3)^(-4)x\ 3^(-1)x\ 6^(-1)

Solve for x (1)/( 2x -3) + (1)/(x -5) =1," " x ne 3/2,5

If (6x+1)/3 + 1 = (x-3)/6 , then x = ?

Solve: 1/((x-1)(x-2))+1/((x-2)(x-3))+1/((x-3)(x-4))=1/6[x!=1,2,3,4]

The number of real of the equation (2x -3)/(x-1) +1 =(6x^2 -x-6)/(x-1) is