What is Delta n for combustion of 1 mole...

What is `Delta n` for combustion of 1 mole of benzene, when both the reactants and the products are gas at 298 K?

`0`

`3/2`

`(-3)/2`

`1/2`

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The combustion of 1 mole of benzene takes place at 298K and 1 atm. After combustion, CO_(2(g)) and H_(2)O_((l)) are produced and 3267.0 KJ of heat is liberated. Calculate the standard enthalpy of formation, Delta_(f)H^(0) of benene. Standard enthalpies of formation of CO_(2(g))andH_(2)O_((l)) are -393.5 KJ mol^(-1) and - 285.83 KJ mol^(-1) respectively

The combustion of 1 mol of benzene takes place at 298 K and 1 atm . After combustion, CO_(2)(g) and H_(2)O(l) are produced and 3267.0 kJ of heat is librated. Calculate the standard entalpy of formation, Delta_(f)H^(Θ) of benzene Given: Delta_(f)H^(Θ)CO_(2)(g) = -393.5 kJ mol^(-1) Delta_(f)H^(Θ)H_(2)O(l) = -285.83 kJ mol^(-1) .

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Which gas is most dense at 1 atm and 298 K ?

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