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Given: (i) S+O2 to SO2, Delta H=-298.2...

Given:
(i) `S+O_2 to SO_2, Delta H=-298.2 kJ`
(ii) `SO_2 + 1/2 O_2 to SO_3, Delta H=-98.7 kJ`
(iii) `SO_3 + H_2 O to H_2 SO_4, Delta H=-130.2 kJ`
(iv) `H_2 + 1/2 O_2 to H_2 O, Delta H=-287.3 kJ` ,
Then the enthalpy of formation of `H_2 SO_4` at 298 K will be _________ .

A

`-814.4`kJ

B

`+320.5`kJ

C

`-650.3`kJ

D

`-933.7`kJ

Text Solution

Verified by Experts

The correct Answer is:
A
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If, S+O_2 rarr SO_2, Delta H =-298.2 kj SO_2 + 1/2 O_2 rarr SO_3, Delta H=-98.7 kJ SO_3 + H_2 O rarrr H_2SO_4 , Delta H =-130.2 kJ H_2 + 1/2 O_2 rarr H_2 O, Delta H =-227.3 kJ Find Delta H for formation of H_2SO_4 at 298 K.

If S+O_(2)toSO_(2),DeltaH=-298.2 " kJ" " mole"^(-1) SO_(2)+(1)/(2)O_(2)toSO_(3)DeltaH=-98.7 " kJ" " mole"^(-1) SO_(3)+H_(2)OtoH_(2)SO_(4),DeltaH=-130.2 " kJ" " mole"^(-1) H_(2)+(1)/(2)O_(2)toH_(2)SO_(4),DeltaH=-287.3 " kJ" " mole"^(-1) the enthlapy of formation of H_(2)SO_(4) at 298 K will be

If {:(SO_(2)+1/2O_(2) rarr SO_(3),DeltaH = -98.7 kJ),(SO_(3)+H_2O rarr H_(2)SO_(4),DeltaH = -130.2 kJ),(H_(2)+1/2O_(2) rarr H_2O , Delta H = -287.3 kJ),(S + H_2 + 2O_(2) rarr H_2SO_4, DeltaH = -814.4 kJ):} Then enthaply of SO_(2) at 298 K is:

Given: 2C_((s)) + 2O_(2(g)) to 2CO_(2(g)), Delta H_1 =-767 kJ …(i) H_(2(g)) + 1/2 O_(2(g)) to H_2 O_((l)), Delta H_2 =-266 kJ …(ii) C_2 H_(2(g)) + 5/2 O_2 to 2CO_(2(g)) + H_2 O_((l)) , Delta H_3 =-1290 kJ ….(iii) Heat of formation of acetylene is _________ .

DeltaS_(sur) for H_(2)+1//2O_(2) rarr H_(2)O, Delta H = -280 KJ at 400 K is

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