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The H-H bond energy is 430KJmol^(-1) and...

The `H-H` bond energy is `430KJmol^(-1)` and `Cl-Cl` bond energy is `240KJmol^(-1)` . `DeltaH` for `HCl` is `-90KJ` . The `H-Cl` bond energy is about

A

180 kJ`mol^-1`

B

360 kJ`mol^-1`

C

213 kJ`mol^-1`

D

425 kJ`mol^-1`

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The correct Answer is:
D
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The H-H bond energy is 430KJ mol^(-1) and Cl-Cl bonds is 240KJ mol^(-1) . DeltaH for HCl is -90KJ . The H-Cl bond energy is about.

The C-Cl bond energy can be calculated from:

From the following bond energies :- H-H "bond energy" = 420 KJmol^(-1) C=-c "bond energy" = 601 KJmol^(-1) C-C "bond energy"=340KJmol^(-1) C-H "bond energy" = 425 KJ mol^(-1) Enthalpy for the reaction :- C_(2)H_(2)+2H_(2)toC_(2)H_(6)

Bond energies of H-H and Cl-Cl are "430 kJ mol"^(-1) and "242 kJ mol"^(-1) respectively. DeltaH_(f) for HCl is "91 kJ mol"^(-1) . What will be the bond energy of H-Cl ?

From the following bond energies: H--H bond energy: 431.37KJmol^(-1) C=C bond energy: 606.10KJmol^(-1) C--C bond energy: 336.49KJmol^(-1) C--H bond energy: 410.50KJmol^(-1) Enthalpy for the reaction will be: overset(H)overset(|)underset(H)underset(|)(C)=overset(H)overset(|)underset(H)underset(|)(C)+H-H to Hoverset(H)overset(|)underset(H)underset(|)(C)-overset(H)overset(|)underset(H)underset(|)(C)-H

From the following bond energies H-H bond energy 431.37 kJ mol^(-1) C=C bond energy 606.10 kJ mol^(-1) C-C bond energy 336.49 kJ mol^(-1) C-H bond energy 410.5 kJ mol^(-1) Enthalpy for the reaction overset(H)overset(|)underset(H)underset(|)(C )=overset(H)overset(|)underset(H)underset(|)(C )+H-HtoH-overset(H)overset(|)underset(H)underset(|)(C )-overset(H)overset(|)underset(H)underset(|)(C )-H will be

TARGET PUBLICATION-CHEMICAL THERMODYNAMICS AND ENERGETICS -COMPETITIVE THINKING
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  4. Deltaf H of HCl is .

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