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The period of oscillation of a simple pe...

The period of oscillation of a simple pendulum is `T = 2pisqrt((L)/(g))`. Meaured value of `L` is `20.0 cm` know to `1mm` accuracy and time for `100` oscillation of the pendulum is found to be `90 s` using a wrist watch of `1 s` resolution. The accracy in the determinetion of `g` is :

A

0.02

B

0.03

C

0.01

D

0.05

Text Solution

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The correct Answer is:
b
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