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A particle is moving in a circular path ...

A particle is moving in a circular path with a constant speed. If `theta` Is the angular displacement, then starting from `theta=0` , the maximum and minimum change in the linear momentum will occur when value of `theta` is respectively

A

`0^(@) and 90^(@)`

B

`90^(@) and 180^(@)`

C

`180^(@) and 270^(@)`

D

`180^(@) and 360^(@)`

Text Solution

Verified by Experts

The correct Answer is:
D

When ` theta = 180^(@)`

Change in monentum `=mv -(-mv ) = 2mv`
This is maximum . When it will return to its intial position ` theta = 360^(@)` , and change in momentum `= mv - mv =0`.
this is minimum
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