A particle starts from rest and moves in a circular motion with constant angular acceleration of `2 rad s^-2`. Find (a) Angular velocity (b) Angular displacement of the particle after `4 s`. ( c) The number of revolutions completed by the particle during these `4 s`. (d) If the radius of the circle is `10 cm`, find the magnitude and direction of net acceleration of the particle at the end of `4 s`.
A
`30 ` radian
B
40 radius
C
50 radium
D
60radian
Text Solution
Verified by Experts
The correct Answer is:
D
Comparing with `S= ut +(1)/(2) at^(2) ,` we have ` theta = omega_(0) t +(1)/(2)alpha t^(2)=2xx5+(1)/(2)+(1)/(2) xx4xx25` `=10+50=60 ` radius
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