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The angular displacement of a particle i...

The angular displacement of a particle is given by `theta = t^3 + 2t +1`, where `t` is time in seconds. Its angular acceleration at `t=2s` is

A

`a+2b+3c`

B

`2b+6ct`

C

`2b -8ct`

D

`2b+12ct`

Text Solution

Verified by Experts

The correct Answer is:
B

`theta = at +bt^(2)+ct^(2) +ct^(3) therefore (d theta ) /(dt) =a +2 bt +3ct^(2)`
`(d^(2)theta)/(dt^(2))=2b+3c xx2t =2b +6ct `
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