A particle of mass `M` is revolving along a circule of radius `R` and another particle of mass `m` is revolving in a circle of radius `r`. If time periods of both particles are same, then the ratio of their angular velocities is
A
`(R )/(r )`
B
`(r )/(R )`
C
`1`
D
`((R )/(r ))^(2)`
Text Solution
Verified by Experts
The correct Answer is:
C
`T_(1) = T_(2) therefore omega_(1)= omega_(2) `
Topper's Solved these Questions
CIRCULAR MOTION
MARVEL PUBLICATION|Exercise TEST YOUR GRASP-1|1 Videos
CIRCULAR MOTION
MARVEL PUBLICATION|Exercise TEST YOUR GRASP-2|1 Videos
ATOMS, MOLECULES AND NUCLEI
MARVEL PUBLICATION|Exercise TEST YOUR GRASP|30 Videos
COMMUNICATION SYSTEMS
MARVEL PUBLICATION|Exercise TEST YOUR GRASP -20|10 Videos
Similar Questions
Explore conceptually related problems
A particle of mass M is revolving along a circule of radius R and nother particle of mass m is recolving in a circle of radius r . If time periods of both particles are same, then the ratio of their angular velocities is
Two particles of mass M and m are moving in a circle of radii R and r. if their time period are the same, what will be the ratio of their linear velocities?
A particle of mass m is moving along a circle of radius r with a time period T . Its angular momentum is
If KE of the particle of mass m performing UCM in a circle of radius r is E. Find the acceleration of the particle
A particle of mass m is being circulated on a vertical circle of radius r. If the speed of particle at the highest point be v, then
A particle travels along a semicircle of radius R in 2 s. The velocity of the particle is
Two particles having mass 'M' and 'm' are moving in a circular path having radius R & r respectively. If their time period are same then the ratio of angular velocity will be : -
Centripetal acceleration of a particle of mass m moving in a circle of radius r is 4//r^(2) . What is the angular momentum of the particle ?
MARVEL PUBLICATION-CIRCULAR MOTION-TEST YOUR GRASP-20