The average acceleration vector for a particle having a uniform circular motion is
A
A constant vector of magnitude `(v^(2))/(r ) `
B
A vector of magnitude ` (v^(2))/(r )` directed normal to the plane of the given uniform circular motion
C
Equal to the instantaneous acceleration vector at the start of the motion
D
A null vector
Text Solution
Verified by Experts
The correct Answer is:
D
For a particle performing a S.H.M the change in velocity is zero during one completed revolution . ` therefore ` Average acceleration `=(dv ) /(dt)=0` `therefore ` The average acceleration vector is a null vector .
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