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A particle moves in a circular path of r...

A particle moves in a circular path of radius 0.4 m with a constan speed . If it makes 5 revolution in each second of its motion , then the speed of the particle will be

A

`(2pi ^(2)p)/(t) m//s`

B

`(2pi ^(2))/(p t)m//s`

C

`(pi^(2) p)/(t) m//s`

D

`(2pi p)/( t) m//s`

Text Solution

Verified by Experts

The correct Answer is:
A
No. of revolutions / sec `=(p) /(t) = n`
`therefore omega = 2pi n =( 2pi P)/(t) `
` and v=r omega =(pi (2pi p))/(t) =( 2pi ^(2) p)/(t)`
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