Ration of angular velocity of hour hand of a clock to self rotation of the earth is
A
`omega _(2) =(omega_(1))/(2)`
B
`omega_(1)=(omega_(1))/(2) `
C
`omega _(2) = (omega _(1))/(16)`
D
`omega_(1)=(omega_(2))/(16)`
Text Solution
Verified by Experts
The correct Answer is:
B
For the earth , `T_(1) =24` h and for the hour hand `T_(2) = 12 h and omega=(2pi)/(T)` ` therefore omega_(1) = (2pi)/(24) and omega_(2) = (2pi)/(12) therefore omega_(1) =(omega_(2))/(2)`
Topper's Solved these Questions
CIRCULAR MOTION
MARVEL PUBLICATION|Exercise TEST YOUR GRASP-1|1 Videos
CIRCULAR MOTION
MARVEL PUBLICATION|Exercise TEST YOUR GRASP-2|1 Videos
ATOMS, MOLECULES AND NUCLEI
MARVEL PUBLICATION|Exercise TEST YOUR GRASP|30 Videos
COMMUNICATION SYSTEMS
MARVEL PUBLICATION|Exercise TEST YOUR GRASP -20|10 Videos
Similar Questions
Explore conceptually related problems
Angular velocity of hour hand of a watch is
Angular velocity of hour arm of a clock, in rad//s , is
The angular speed of rotation of the earth is
Which is greater : the angular velocity of hour hand of a watch or angular velocity of earth around its own axis ? Give their ratio.
Calculate the angular speed of the hour hand of a clock .
Angular speed of hour hand of a clock in degree per second is
Calculate the angular velcity of the minute s hand of a clock.
Find the angular speed of the minute hand of a clock.
MARVEL PUBLICATION-CIRCULAR MOTION-TEST YOUR GRASP-20