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The relation between tangential or linea...

The relation between tangential or linear acceleration and angular acceleration of a body moving in circle is given by

A

`alpha =(a v)/(omega )`

B

`alpha = (vomega)/(a)`

C

`alpha = (omega )/(a v)`

D

`alpha =(aomega )/(v)`

Text Solution

Verified by Experts

`a= r alpha therefore alpha =(a) /(r ) "But" v= r omega therefore r=(v)/(omega)`
` therefore alpha= (a)/((v)/(omega))=(a omega )/(v)`
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