A particle moves on circular path of radius 5 m with constant speed 5 m/s. Find the magnitude of its average acceleration when it completes half revolution.
A
`(v^(2))/(2R)`
B
`(2v^(2))/(piR)`
C
`(v^(2))/(R )`
D
`(v^(2))/(pi R)`
Text Solution
Verified by Experts
The correct Answer is:
B
When the particle goes from A to B the change in its velocity `= V-(-V) = 2V ` and the time taken to travel the distance from A to B along the circular path is `t= ( "distance ") /( "speed")=(pi R )/(v)` ` therefore `Average acceleration `=(dv)/(dt)=(2v)/((pi R )/(v))=(2v^2)/(pi R)`
Topper's Solved these Questions
CIRCULAR MOTION
MARVEL PUBLICATION|Exercise TEST YOUR GRASP-1|1 Videos
CIRCULAR MOTION
MARVEL PUBLICATION|Exercise TEST YOUR GRASP-2|1 Videos
ATOMS, MOLECULES AND NUCLEI
MARVEL PUBLICATION|Exercise TEST YOUR GRASP|30 Videos
COMMUNICATION SYSTEMS
MARVEL PUBLICATION|Exercise TEST YOUR GRASP -20|10 Videos
Similar Questions
Explore conceptually related problems
A particle is moving along a circular along a circular path of radius 5 m with a uniform speed 5ms^(-1) . What will be the average acceleration when the particle completes half revolution?
A particle is moving along circular path of radius 40 m with a uniform speed of 20m//s . Then the time taken for the particle to complete half revolution will be
A partical is moving along a circular path of radius 5m and with uniform speed 5 m//s . What will be the avarage acceleration when the partical completes half revoluation?
A particle is moving along a circular path of radius 6 m with uniform speed of 8 ms^(–1) . The average acceleration when the particle completes one half of the revolution is -
A particle moves in a circular path of radius 0.5 m with a linear speed of 2 ms^(-1) ,its angular speed is
A particle of mass 2 kg moves on a circular path with constant speed 10 m // s . Find change in speed and magnitude of change in velocity. Whan particle completes half revolution.
A particle is revolving in a circular path of radius 2 m with constant angular speed 4 rad/s. The angular acceleration of particle is
A particle is revoiving in a circular path of radius 25 m with constant angular speed 12 rev/min. then the angular acceleration of particle is
A Particle of mass 'M' moves in a uniform circular path of radius 'r' with a constant speed 'v' then its centripetal acceleration is .
A particle moves in a circle of radius R = 21/22 m with constant speed 1 m//s. Find, (a) magnitude of average velocity and (b) magnitude of average acceleration in 2 s.
MARVEL PUBLICATION-CIRCULAR MOTION-TEST YOUR GRASP-20
