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If the momentum of a body increases by 0...

If the momentum of a body increases by 0.01%, its kinetic energy will increase by

A

`44%`

B

`55%`

C

`60%`

D

`77 %`

Text Solution

Verified by Experts

The correct Answer is:
A

`K=(P^(2))/(2m) ,K ' =(((120P)/(100))^(2))/(2m)`
`=1.44 (P^(2))/(2m) = 1.44 K `
`therefore Delta K=K' -K = 0.44 K=44%`
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