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Figure shows a body of mass m moving wit...

Figure shows a body of mass m moving with a uniform speed v along a circle of radius r . The change in velocity in going from A to B is

A

`(v )/(sqrt(2))`

B

`v`

C

zero

D

`vsqrt(2)`

Text Solution

Verified by Experts

The correct Answer is:
D

The body is moving with a uniform speed but the direction of its velocity changes from point and at any point it is directed along the tangent
Its velocity at `A = V_(A ) = hatj v `
and its velocity at B is ` V_(B ) = - hatj v`
` therefore ` change in velocity `= vec V_(B) - vecv _(A) =- hati v - hatj v `
`therefore ` magnitude of change of velocity
` = | - hati v- hatj v| = sqrt( v^(2)+v^(2))= vsqrt(2)`
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