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A particle of mass m is moving in a plan...

A particle of mass `m` is moving in a plane along a circular path of radius `r`. Its angular momentum about the axis of rotation is `L`. The centripetal force acting on the particle is.

A

`L^(2) //mr^(2)`

B

`l^(2)//mr^(3)`

C

`L^(2) //mr`

D

`L^(2)//r^3`

Text Solution

Verified by Experts

The correct Answer is:
B

`L= mvr .`
` and F= (mv^(2))/( r ) = (m^(2) v^(2) r^(2) )/( mr ^(3)) = (L^(2))/(mr^(3))`
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